College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.8 - Exponential Growth and Decay Models; Newton's Law: Logistic Growth and Decay Models - 6.8 Assess Your Understanding - Page 486: 2

Answer

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Work Step by Step

$N(t)=1000e^{0.01t},$ a. $N(0)=1000e^{0}=1000$ b. From the formula $N(t)=1000e^{0.01t},$ The growth rate of the population of insect is $0.01$ in $t$ years with the initial population of $1000$ c. $N(4)=1000e^{0.04}=1040.81,$ d. $N(t)=1000e^{0.01t}=1700,$ $e^{0.01t}=17,$ $0.01t=\ln17,$ $t=283.32$ e. $N(t)=1000e^{0.01t}=2000,$ $e^{0.01t}=2,$ $0.01t=\ln2,$ $t=69.32$
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