Answer
See an explanation
Work Step by Step
$N(t)=1000e^{0.01t},$
a. $N(0)=1000e^{0}=1000$
b. From the formula $N(t)=1000e^{0.01t},$ The growth rate of the population of insect is $0.01$ in $t$ years with the initial population of $1000$
c. $N(4)=1000e^{0.04}=1040.81,$
d. $N(t)=1000e^{0.01t}=1700,$
$e^{0.01t}=17,$
$0.01t=\ln17,$
$t=283.32$
e. $N(t)=1000e^{0.01t}=2000,$
$e^{0.01t}=2,$
$0.01t=\ln2,$
$t=69.32$