Chapter 6 - Section 6.8 - Exponential Growth and Decay Models; Newton's Law: Logistic Growth and Decay Models - 6.8 Assess Your Understanding - Page 486: 10

See below.

We know that $x=2xe^{k\cdot1,300,000,000}\\0.5=e^{1,300,000,000k}\\1,300,000,000k=\ln0.5\\k=\frac{\ln0.5}{1,300,000,000}\approx-5.3319\cdot10^{-10}$ Thus $N(100)=10e^{-5.3319\cdot10^{-10}\cdot100}\approx9.99999946681$ $N(1000)=10e^{-5.3319\cdot10^{-10}\cdot1000}\approx9.9999946681$