Answer
See below.
Work Step by Step
We know that $x=2xe^{k\cdot1,300,000,000}\\0.5=e^{1,300,000,000k}\\1,300,000,000k=\ln0.5\\k=\frac{\ln0.5}{1,300,000,000}\approx-5.3319\cdot10^{-10}$
Thus $N(100)=10e^{-5.3319\cdot10^{-10}\cdot100}\approx9.99999946681$
$N(1000)=10e^{-5.3319\cdot10^{-10}\cdot1000}\approx9.9999946681$