Answer
a) $H(-6)=60$
The point is (-6, 60).
b) $x=-4$
The point is (-4, 12).
c) $x=-2$
Work Step by Step
a) $H(-6)=(\frac{1}{2})^{-6}-4=2^6-4=64-4=60$
The point is (-6, 60).
b) $12=(\frac{1}{2})^{x}-4$
$16=(\frac{1}{2})^{x}$
$(\frac{1}{16})^{-1}=(\frac{1}{2})^{x}$
$(\frac{1}{2})^{-4}=(\frac{1}{2})^{x}$
$x=-4$
The point is (-4, 12).
c) $0=(\frac{1}{2})^{x}-4$
$4=(\frac{1}{2})^{x}$
$(\frac{1}{4})^{-1}=(\frac{1}{2})^{x}$
$(\frac{1}{2})^{-2}=(\frac{1}{2})^{x}$
$x=-2$
