## College Algebra (10th Edition)

$x = -4$
The two sides have the same base. Use the rule $a^m=a^n \longrightarrow m=n$ to obtain: $x=3x+8$ Subtract $3x$ to both sides of the equation to obtain: $\begin{array}{ccc} &3-3x &= &3x+8-3x \\&-2x &= &8 \end{array}$ Divide by $-2$ to both sides of the equation to obtain: $\dfrac{-2x}{-2} = \dfrac{8}{-2} \\x = -4$