Answer
a)
$K(C(F))=\frac{5}{9}(F-32)+273$
b) 80 degrees Fahrenheit is almost 300 degrees kelvin.
Work Step by Step
a) We find K(C(F)):
$K(C(F))=\frac{5}{9}(F-32)+273$
b) To convert 80 degrees Fahrenheit to Kelvin, we solve K(C(80)):
$K(C(80))=\frac{5}{9}(80-32)+273=$
$\frac{5}{9}(48)+273=$
$26.\overline{66}+273\approx$
$300$ K