College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.1 - Composite Functions - 6.1 Assess Your Understanding - Page 410: 66

Answer

$\frac{2}{3}\pi r^3$

Work Step by Step

By the text of the exercise $h=2r$, thus $V=\frac{1}{3}\pi r^2 h=\frac{1}{3}\pi r^2\cdot2r=\frac{2}{3}\pi r^3$
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