College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.1 - Composite Functions - 6.1 Assess Your Understanding - Page 408: 21

Answer

1) $\frac{3}{\sqrt[3] 4+1}$ 2) 1 3) 1.2 4) 0

Work Step by Step

If f and g are two functions, then the composite function is denoted by f o g, 1) First evaluate g(4) and then evaluate f(g(4)) g(x) = $\sqrt[3] x$ g(4) = $\sqrt[3] 4$ f(x) = $\frac{3}{x+1}$ f(g(x)) = $\frac{3}{g(x) + 1}$ f(g(4)) = $\frac{3}{\sqrt[3] 4+1}$ 2) First evaluate f(2) and then evaluate g(f(2)) f(x) = $\frac{3}{x+ 1}$ f(2) = $\frac{3}{2+ 1}$ =1 g(x) = $\sqrt[3] x$ g(f(2)) = $\sqrt[3] 1$ g(f(2)) = 1 3) First Evaluate f(1). Substitute the answer into f to evaluate f(f(1)) f(x) = $\frac{3}{x+ 1}$ f(f(x)) = $\frac{3}{f(x)+ 1}$ = $\frac{3}{ \frac{3}{x+ 1}+ 1}$ f(f(1)) = $\frac{3}{ \frac{3}{1+ 1}+ 1}$ f(f(1)) = 1.2 4) First evaluate g(0). Substitute the answer into g to evaluate g(g(0)) g(x) = $\sqrt[3] x$ g(0) =$\sqrt[3] 0$ = 0 g(g(x)) = $\sqrt[3] g(x)$ g(g(0)) = $\sqrt[3] g(0)$ =$\sqrt[3] 0$ g(g(0)) = 0
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.