Answer
$-1.5$
Work Step by Step
We know that $a^b=a^c\longrightarrow b=c$ if $a\ne1,a\ne-1$ (which applies here).
Hence here $4^{x-3}=8^{2x}\\(2^2)^{x-3}=(2^3)^{2x}\\2^{2(x-3)}=2^{6x}\\2(x-3)=6x\\2x-6=6x\\-6=4x\\x=-1.5$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 6 - Cumulative Review - Page 503: 12
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