College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 5 - Section 5.1 - Polynomial Functions and Models - 5.1 Assess Your Understanding - Page 340: 116



Work Step by Step

If $a$ is a zero of a function with multiplicity $b$ then $(x-a)^b$ is a “multiplier” of the function. Hence here $f(x)=k(x+4)(x+1)(x-2)$ $(0,16)$ (because of the y-intercept) is on the graph thus $k\cdot(4)(1)(-2)=16\\-8k=36\\k=-2$ So $f(x)=-2(x+4)(x+1)(x-2)$
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