Answer
$\color{blue}{x \ge \dfrac{3}{2}}$
Refer to the graph below.
Work Step by Step
Subtract $3x$ and add $1$ on both sides of the inequality to obtain:
\begin{array}{ccc}
&3x+2 &\le &5x-1
\\&3x+2-3x+1 &\le &5x-1-3x+1
\\&3 &\le &2x
\end{array}
Divide $2$ to both sides to obtain:
$\dfrac{3}{2} \le \dfrac{2x}{2}
\\\dfrac{3}{2} \le x
\\\color{blue}{x \ge \dfrac{3}{2}}$
To graph the inequality, plot a point at $x=\frac{3}{2}$ then shade the region to its right.
(refer to the attached image in the answer part above)
