## College Algebra (10th Edition)

$\color{blue}{x \ge \dfrac{3}{2}}$ Refer to the graph below.
Subtract $3x$ and add $1$ on both sides of the inequality to obtain: \begin{array}{ccc} &3x+2 &\le &5x-1 \\&3x+2-3x+1 &\le &5x-1-3x+1 \\&3 &\le &2x \end{array} Divide $2$ to both sides to obtain: $\dfrac{3}{2} \le \dfrac{2x}{2} \\\dfrac{3}{2} \le x \\\color{blue}{x \ge \dfrac{3}{2}}$ To graph the inequality, plot a point at $x=\frac{3}{2}$ then shade the region to its right. (refer to the attached image in the answer part above)