College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 5 - Cumulative Review: 4


The linear function is $f(x) = -3x+1$. Refer to the graph below.

Work Step by Step

RECALL: (1) The point-slope form of a line's equation is $y-y_1=m(x-x_1)$ where $(x_1, y_1)$ is a point on the line and $m$ = slope of the line. (2) The slope-intercept form of a line is $y=mx+b$ where $m$ = slope of the line and $b$ = y-intercept of the line. The line has: $m=-3$; contains the point $(-1, 4)$ Use the point-slope form in (1) above to obtain the line's equation: $y-4=-3[x-(-1)] \\y-4=-3(x+1)$ Isolate $y$ on one side to get the slope-intercept form of the line's equation: $y-4+4 = -3(x+1)+4 \\y=-3(x+1)+4 \\y=-3x-3+4 \\y=-3x+1$ Thus, the linear function is $f(x)=3x+1$ To graph the line, perform the following steps: (1) Plot the y-intercept point $(0 ,1)$. (2) Use the slope $-3$ or $\frac{-3}{1}$ to obtain another point on the line. From $(0, 1)$, move 3 units down (the rise) and 1 unit to the right (the run) t arrive at the point $(1, -2)$. (3) Connect the two points using a straight line to complete the graph. (refer to the image in the answer part above for the graph)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.