Answer
$x$-intercepts: $-3$ and $3$
$y$-intercept: $9$
Work Step by Step
RECALL:
(1) The intercepts of a function are the points where its graph touches or crosses the x axis or the y axis.
(2) The x-intercept can be found by letting $y=0$ and then solving for $x$.
(3) The y-intercept can be found by letting $x=0$ and then solving for $y$
Letting $y=0$ and then solving for $x$ gives:
$y=x^2-9
\\0=x^2-9
\\9=x^2
\\\pm\sqrt{9} = \sqrt{x^2}
\\\pm3 = x$
Letting $x=0$ and then solving for $y$ gives:
$y=x^2-9
\\y=0^2-9
\\y=0-9
\\y=9$
Thus, the intercepts of the function are:
$x$-intercepts: $-3$ and $3$
$y$-intercept: $9$
