## College Algebra (10th Edition)

Published by Pearson

# Chapter 3 - Section 3.1 - Functions - 3.1 Assess Your Understanding - Page 211: 61

#### Answer

The domain of p is {$x|x\gt1$}.

#### Work Step by Step

We can only take the square root of a positive number, so it follows that: $x-1\gt0$ $x\gt1$ The domain of p is {$x|x\gt1$}

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