College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 3 - Section 3.1 - Functions - 3.1 Assess Your Understanding: 37

Answer

$y$ is NOT defined as a function of $x$.

Work Step by Step

Note that: When $x=4$, the given equation becomes: $4=y^2 \\\pm\sqrt4 = y \\\pm2 = y$ Since the equation gives two values of $y$ for $x=4$, the equation does not define $y$ as a function of $x$.
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