Answer
false
Work Step by Step
The only restriction to the given function is that $x\ne0$ since the denominator cannot be equal to zero.
The function is defined for both $x=2$ and $x=-2$
Thus, the give statement is false.
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 3 - Section 3.1 - Functions - 3.1 Assess Your Understanding - Page 210: 14
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