College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 3 - Review Exercises: 19

Answer

Even

Work Step by Step

To find out if the function is even, odd, or neither, we find $g(−x)$ and compare the result to $g(x)$: $g(x)=\displaystyle \frac{4+x^{2}}{1+x^{4}}$ $\displaystyle g(-x)=\frac{4+(-x)^{2}}{1+(-x)^{4}}$ $\displaystyle =\frac{4+x^{2}}{1+x^{4}}$ $\displaystyle =g(x)$ Thus $g(x)$ is even.
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