College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 3 - Review Exercises - Page 268: 3

Answer

(a) $f(2)=2$ (b) $f(-2)=-2$ (c) $f(-x)=\dfrac{-3x}{x^2-1}$ (d) $-f(x)=-\dfrac{3x}{x^2-1}$ (e) $f(x-2)=\dfrac{3x-6}{x^2-4x+3}$ (f) $f(2x)=\dfrac{6x}{4x^2-1}$

Work Step by Step

(a) $f(2)=\dfrac{3(2)}{2^2-1}=\dfrac{6}{3}=2$ (b) $f(-2)=\dfrac{3(-2)}{(-2)^2-1}=\dfrac{-6}{3}=-2$ (c) $f(-x)=\dfrac{3(-x)}{(-x)^2-1}=\dfrac{-3x}{x^2-1}$ (d) $-f(x)=-\dfrac{3x}{x^2-1}$ (e) $f(x-2)=\dfrac{3(x-2)}{(x-2)^2-1}=\dfrac{3x-6}{x^2-4x+4-1}=\dfrac{3x-6}{x^2-4x+3}$ (f) $f(2x)=\dfrac{3(2x)}{(2x)^2-1}=\dfrac{6x}{4x^2-1}$
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