Answer
$x^2-8x+y^2+6y=0$
Work Step by Step
The general equation for a circle with radius $r$ and centre $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$, hence our equation:
$(x-4)^2+(y+3)^2=5^2\\x^2-8x+16+y^2+6y+9=25\\x^2-8x+y^2+6y=0$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 2 - Test - Page 196: 8
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