College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Test - Page 196: 11

Answer

Resistance would be 14.69 ohms

Work Step by Step

The resistance (in ohms) (R) of a circular conductor varies directly with the length L of the conductor and inversely with the square of the radius (A) of the conductor. =>$R = k\frac{L}{A^2}$ Given R = 10 ohms when L = 50 feet and $A = 6 \times 10^{-3} $ inch => $10 = k\frac{50}{(6 \times 10^{-3})^2}$ => $k = 7.2 \times 10^{-6}$ To find R when L = 100 feet and $A = 7 \times 10^{-3} $ inch => $R = 7.2 \times 10^{-6} \times \frac{100}{(7 \times 10^{-3})^2} = 14.69\ ohms$
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