College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.5 - Variation - 2.5 Assess Your Understanding - Page 191: 9



Work Step by Step

$F$ varies inversely with $d^2$, so the equation that represents the variation is: $F=\dfrac{k}{d^2}$ Since $F=10$ when $d=5$ , substituting these into the tentative equation above gives: $F=\dfrac{k}{d^2} \\10=\dfrac{k}{5^2} \\10=\dfrac{k}{25} \\25(10) = \dfrac{k}{25} \cdot 25 \\250=k$ Thus, the equation of the inverse variation is: $\color{blue}{F=\dfrac{250}{d^2}}$
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