College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.5 - Variation - 2.5 Assess Your Understanding - Page 191: 6

Answer

$\color{blue}v=8t$

Work Step by Step

$v$ varies directly with $t$, so the equation that represents the variation is: $v=kt$ Since $v=16$ when $t=2$, substituting these into the tentative equation above gives: $v=kt \\16=k(2) \\\frac{16}{2} = k \\8=k$ Thus, the equation of the direct variation is: $\color{blue}v=8t$
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