Answer
$x^4y^{16}$
Work Step by Step
$(\frac{x^2y^{-3}}{x^4y^5})^{-2}=(\frac{1}{x^2y^8})^{-2}=(x^2y^8)^2=x^4y^{16}$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.