College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.3 - Lines - 2.3 Assess Your Understanding - Page 180: 117

Answer

$C=0.60x+39$ ${{\$}} 105.00\quad$ for 110 miles ${{\$}} 177.00\quad$ for 230 miles

Work Step by Step

Total cost $=$ (cost per mile)(number of miles) $+$ fixed cost Let $C=$ cost in dollars. $x=$ number of miles driven, Fixed cost =39 A linear equation: $C=0.60x+39$ When $x=110,$ $C=(0.60)(110)+39={{\$}} 105.00.$ When x=$230,$ $\mathrm{C}=(0.60)(230)+39={{\$}} 177.00.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.