College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.1 - The Distance and Midpoint Formulas - 2.1 Assess Your Understanding - Page 156: 69


$a. \quad(2.65,1.6)$ $b. \quad \approx 1.285$ units

Work Step by Step

$a.$ The shortest side is between $(2.6,1.5)$ and $(2.7,1.7)$. Midpoint: $(\displaystyle \frac{x_{1}+x_{2}}{2},\displaystyle \frac{y_{1}+y_{2}}{2})=(\frac{2.6+2.7}{2},\frac{1.5+1.7}{2})=(\frac{5.3}{2},\frac{3.2}{2})$ $=(2.65,1.6)$ $b.$ Distance between $(1.4,1.3)$ and $(2.65,1.6)$: $d=\sqrt{(2.65-1.4)^{2}+(1.6-1.3)^{2}}$ $=\sqrt{(1.25)^{2}+(0.3)^{2}}$ $=\sqrt{1.5625+0.09}$ $=\sqrt{1.6525}$ $\approx 1.285$ units
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