College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.1 - The Distance and Midpoint Formulas - 2.1 Assess Your Understanding - Page 155: 52

Answer

$B=(5,-5)$

Work Step by Step

The midpoint $M=(x,y)$ of the line segment from $P_{1}=(x_{1},y_{1})$ to $P_{2}=(x_{2},y_{2})$ is $M=(x,y)=(\displaystyle \frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$ --- Given $A=(-1,8),B=(x,y),M=(2,3)$ $ \begin{aligned} & & & & & & \\ \frac{-1+x}{2} & =2 & /\times 2 & & \frac{8+y}{2} & =3 & /\times 2\\ -1+x & =4 & /+1 & & 8+y & =3 & /-8\\ x & =5 & & & y & =-5 & \end{aligned}$ $B=(5,-5)$
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