College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.1 - The Distance and Midpoint Formulas - 2.1 Assess Your Understanding - Page 155: 28


$5\sqrt{5}$ units.

Work Step by Step

RECALL: The distance $d$ between the points $(x_1, y_1)$ and $(x_2, y_2)$ can be found using the distance formula: $d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ Use the formula above to obtain: $d=\sqrt{(-4-6)^2+(-3-2)^2} \\d=\sqrt{(-10)^2+(-5)^2} \\d=\sqrt{100+25} \\d=\sqrt{125} \\d=\sqrt{25(5)} \\d=\sqrt{5^2(5)} \\d=5\sqrt{5}$ Thus, the distance between the two given points is $5\sqrt{5}$ units.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.