College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.3 - Probability - 10.3 Assess Your Understanding - Page 706: 67

Answer

See below.

Work Step by Step

a) P(1 or 2 TV sets)=$P(1)+P(2)=0.24+0.33=0.57$ b) P(1 or more TV sets)=$P(1)+P(2)+P(3)+P(\geq4)=0.24+0.33+0.21+0.17=0.95$ c)P(3 or fewer TV sets)=$P(0)+P(1)+P(2)+P(3)=0.05+0.24+0.33+0.21=0.83$ d)P(3 or more TV sets)=$P(3)+P(\geq4)=0.21+0.17=0.38$ e)P(fewer than 2 TV sets)=$P(0)+P(1)=0.05+0.24=0.29$ f) P(less than 1 TV set)=$P(0)=0.05$ g)P(1, 2 or 3 TV sets)=$P(1)+P(2)+P(3)=0.24+0.33+0.21=0.78$ h)P(2 or more TV sets)=$P(2)+P(3)+P(\geq4)=0.33+0.21+0.17=0.71$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.