College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Cumulative Review - Page 710: 7

Answer

2

Work Step by Step

Using log rules, we obtain: $\log_3{9}=\log_3{3^2}=2\log_3{3}=2$
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