Answer
$x=\frac{1+_{-} \sqrt 2 *i}{3}$
Work Step by Step
$3x^2-2x+1=0$
$x=\frac{-b+_{-} \sqrt {b^2-4ac}}{2a}$
$x=\frac{2+_{-} \sqrt {4-4*3}}{2*3}$
$x=\frac{1+_{-} \sqrt 2 *i}{3}$
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