Answer
$x=\pm 2$
Work Step by Step
We solve:
$x^{4}-3x^{2}-4=0$
$(x^{2}-4)(x^{2}+1)=0$
$x^{2}-4=0$ or $x^{2}+1=0$
$x^{2}=4$ or $x^{2}=-1$
$x=\pm\sqrt{4}$ or $x=\pm\sqrt{-1}$=not real
$x=\pm 2$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Test - Page 147: 3
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