College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Test: 4


$\displaystyle x=\frac{9}{2}$

Work Step by Step

We solve: $\sqrt{2x-5}+2=4$ $\sqrt{2x-5}=4-2=2$ $(\sqrt{2x-5})^{2}=2^{2}$ $2x-5=4$ $2x=4+5=9$ $x=\frac{9}{2}$
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