College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding - Page 134: 90


$-3\leq x\leq 3$

Work Step by Step

We know that the solution to the inequality: $x^2\lt a$ Is equivalent to: $-\sqrt{a}\lt x\lt \sqrt{a}$ Therefore: $x^{2}\leq 9$ $-\sqrt{9}\leq x\leq\sqrt{9}$ $-3\leq x\leq 3$
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