College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding - Page 134: 87


$x\leq-3$ or $x\geq 3$

Work Step by Step

We know that the solution to the inequality: $x^2\gt a$ Is equivalent to: $x\lt -\sqrt{a}$ or $x\gt \sqrt{a}$ Therefore: $x^{2}\geq 9$ $x\leq-\sqrt{9}$ or $x\geq\sqrt{9}$ $x\leq-3$ or $x\geq 3$
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