#### Answer

The solution set is $\left\{0, 64\right\}$.

#### Work Step by Step

Square both sides to obtain:
$x^2=(8\sqrt{x})^2$
Use the rule $(ab)^m = a^mb^m$ to obtain:
$x^2=8^2(\sqrt{x})^2
\\x^2=64x$
Subtract $64x$ on both sides of the equation to obtain:
$x^2-64=64x-64x
\\x^2-64x=0$
Factor out $x$ to obtain:
$x(x-64) = 0$
Equate each factor to zero, and then solve each equation to obtain:
$\begin{array}{ccc}
&x=0 &\text{ or } &x-64=0
\\&x=0 &\text{ or } &x=64
\end{array}$
Thus, the solution set is $\left\{0, 64\right\}$.