## College Algebra (10th Edition)

$-13$
Add 3 on both sides of the equation to obtain: $\sqrt[3]{1-2x}-3+3=0+3 \\\sqrt[3]{1-2x}=3$ Cube both sides of the equation to obtain: $1-2x=3^3 \\1-2x=27$ Subtract 1 on both sides to obtain: $-2x = 26$ Divide -2 to both sides of the equation to obtain: $x=\frac{26}{-2} \\x=-13$ Thus, the solution is $\left\{-13\right\}$.