Answer
$x=-1$
Work Step by Step
$x^{2}+2x+5=4$
Subtracting $5$ from both sides, we get
$x^{2}+2x=-1$
Add $(\frac{b}{2})^{2}=(\frac{2}{2})^{2}=1$ to both sides to complete the square.
$x^{2}+2x+1=0$
$\implies (x+1)^{2}=0$
Taking square root on both sides, we have
$x+1=0$
Subtracting $1$ from both sides, we have
$x=-1$
The solution of the equation is $x=-1$.
