Chapter 9 - Solving Quadratic Equations - Chapter Review - Page 535: 16

$x=6$ and $x=-10$.

$(x+2)^{2}=64$ Taking square root on both sides, we get $x+2=\pm\sqrt {64}$ $\implies x+2=\pm 8$ Subtracting $2$ from both sides, we obtain $x=-2\pm 8$ So, the solutions are $x=-2+8=6$ and $x=-2-8=-10$.