Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.5 - Solving Quadratic Equations Using the Quadratic Formula - Exercises - Page 522: 45

Answer

Hence, the first step is wrong and the correct answers are $x=3$ and $x=-\frac{2}{3}$

Work Step by Step

The given equation is $\Rightarrow 3x^2-7x-6=0$ Use Quadratic Formula. $\Rightarrow x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ Substitute $3$ for $a,-7$ for $b$ and $-6$ for $c$. $\Rightarrow x=\frac{-(-7)\pm\sqrt{(-7)^2-4(3)(-6)}}{2(3)}$ Simplify. $\Rightarrow x=\frac{7\pm\sqrt{49+72}}{6}$ $\Rightarrow x=\frac{7\pm\sqrt{121}}{6}$ $\Rightarrow x=\frac{7\pm11}{6}$ The solutions are $x=\frac{7+11}{6}=\frac{18}{6}=3$ and $x=\frac{7-11}{6}=\frac{-4}{6}=-\frac{2}{3}$ Hence, the first step is wrong and the correct answers are $x=3$ and $x=-\frac{2}{3}$
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