Answer
No
Work Step by Step
$$y=(x-5)^2$$
Here the graph of this function will open up as $a>0$ and it has a minimum value. Also it has one positive $x$-intercept, $x=5$, meaning that the vertex is on the positive side of $x$-axis. So the given graph could not represent the function as the vertex is on the negative side of the $x$-axis.