#### Answer

$x=1.45$ and $x=-3.45$

#### Work Step by Step

The given equation is
$\Rightarrow x^2+2x=5$
Find the value of $(\frac{b}{2})^2$.
Substitute $2$ for $b$.
$=(\frac{2}{2})^2$
Simplify.
$=(1)^2$
$=1$
Add $1$ to each side of the equation.
$\Rightarrow x^2+2x+1=5+1$
Simplify.
$\Rightarrow x^2+2x+1=6$
Write the left side as the square of a binomial.
$\Rightarrow (x+1)^2=6$
Take the square root of each side.
$\Rightarrow x+1=\pm \sqrt{6}$
Subtract $1$ from each side.
$\Rightarrow x+1-1=\pm \sqrt{6} -1$
Simplify.
$\Rightarrow x=\pm \sqrt{6} -1$
The solutions are $x=\sqrt{6} -1=1.45$ and $x=-\sqrt{6} -1=-3.45$.