Answer
$I=\frac{7\sqrt {15}}{5}\approx 5.42\text{ amperes}$
Work Step by Step
$I=\sqrt {\frac{P}{R}}=\sqrt{\frac{147}{5}}=\frac{\sqrt {147}}{\sqrt{5}}=\frac{\sqrt {147}}{\sqrt {5}}\cdot \frac{\sqrt {5}}{\sqrt{5}}$
$=\frac{\sqrt {49}\sqrt{3}\sqrt {5}}{5}=\frac{7\sqrt {15}}{5}$
$I=\frac{7\sqrt {15}}{5}\approx 5.42\text{ amperes}$
