Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 486: 62

Answer

a) $P=d\sqrt d$ d) $11.86$ Earth years

Work Step by Step

$$P=\sqrt{d^3}$$ a) Simplify: $$P=\sqrt{d^2\cdot d}=\sqrt{d^2}\cdot\sqrt {d}=|d|\sqrt{d}=d\sqrt d$$ because $d\geq 0$. b) Find $P$ when $d=5.2$: $$P=5.2\sqrt{5.2}\approx11.86~~\text{Earth years}$$
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