Answer
$(x-5)(4x+1)$.
Work Step by Step
The given polynomial is
$=4x^2-19x-5$
Rewrite $-19x$ as $-20x+x$.
$=4x^2-20x+x-5$
Group the terms.
$=(4x^2-20x)+(x-5)$
Factor each group.
$=4x(x-5)+1(x-5)$
Factor out $(x-5)$.
$=(x-5)(4x+1)$
Hence, the factor of the polynomial is $(x-5)(4x+1)$.
