Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.6 - Factoring ax^2 + bx + c = 0 - Monitoring Progress - Page 393: 2

Answer

$(7x+5)(2x+3)$.

Work Step by Step

The given polynomial is $=14x^2+31x+15$ Rewrite $31x$ as $10x+21x$. $=14x^2+10x+21x+15$ Group the terms. $=(14x^2+10x)+(21x+15)$ Factor each group. $=2x(7x+5)+3(7x+5)$ Factor out $(7x+5)$. $=(7x+5)(2x+3)$ Hence, the factor of the polynomial is $(7x+5)(2x+3)$.
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