Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.2 - Multiplying Polynomials - Exercises - Page 369: 41

Answer

$18e^3-27e^2+37e+7$.

Work Step by Step

The given expression is $=(3e^2-5e+7)(6e+1)$ Distribute $(6e+1)$ to each term of $(3e^2-5e+7)$. $=3e^2(6e+1)-5e(6e+1)+7(6e+1)$ Use distributive property. $=3e^2(6e)+3e^2(1)-5e(6e)-5e(1)+7(6e)+7(1)$ Multiply. $=18e^3+3e^2-30e^2-5e+42e+7$ Combine like terms. $=18e^3-27e^2+37e+7$ Hence, the product is $18e^3-27e^2+37e+7$.
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