Answer
$y^3+11y^2+22y-6$.
Work Step by Step
The given expression is
$=(y+3)(y^2+8y-2)$
Distribute $(y^2+8y-2)$ to each term of $(y+3)$.
$=y(y^2+8y-2)+3(y^2+8y-2)$
Use distributive property.
$=y(y^2)+y(8y)+y(-2)+3(y^2)+3(8y)+3(-2)$
Multiply.
$=y^3+8y^2-2y+3y^2+24y-6$
Combine like terms.
$=y^3+11y^2+22y-6$
Hence, the product is $y^3+11y^2+22y-6$.
