Answer
$y=1400(1.05)^{2t}$.
Work Step by Step
The given values are
Initial amount $P=\$1400$.
Rate of interest $r=10\%=0.10$.
Number of time interest is compounded per year.
$n=2$.
Formula for the compound interest
$\Rightarrow y=P(1+\frac{r}{n})^{nt}$
Substitute all the values.
$\Rightarrow y=1400(1+\frac{0.10}{2})^{2t}$
Simplify.
$\Rightarrow y=1400(1+0.05)^{2t}$
$\Rightarrow y=1400(1.05)^{2t}$.
