Answer
$y=2000(1.0125)^{4t}$
Work Step by Step
The given values are
Initial amount $P=\$2000$.
Rate of interest $r=5\%=0.05$.
Number of time interest is compounded per year.
$n=4$.
Formula for the compound interest
$\Rightarrow y=P(1+\frac{r}{n})^{nt}$
Substitute all the values.
$\Rightarrow y=2000(1+\frac{0.05}{4})^{4t}$
Simplify.
$\Rightarrow y=2000(1+0.0125)^{4t}$
$\Rightarrow y=2000(1.0125)^{4t}$.
