Answer
The solution is $(6,7)$.
Work Step by Step
The given system of equations is
$\Rightarrow 2x=12$ ...... (1)
$\Rightarrow x-5y=-29$ ...... (2)
Isolate $x$ in equation (1).
$\Rightarrow x=6$ ...... (3)
Substitute $6$ for $x$ in equation (2).
$\Rightarrow 6-5y=-29$
Add $5y+29$ to each side.
$\Rightarrow 6-5y+5y+29=-29+5y+29$
Simplify.
$\Rightarrow 35=5y$
Divide each side by $5$.
$\Rightarrow \frac{35}{5}=\frac{5y}{5}$
Simplify.
$\Rightarrow 7=y$
Check
Equation (1)
$\Rightarrow 2x=12$
$\Rightarrow 2(6)=12$
$\Rightarrow 12=12$
True.
Check
Equation (2)
$\Rightarrow x-5y=-29$
$\Rightarrow 6-5(7)=-29$
$\Rightarrow 6-35=-29$
$\Rightarrow -29=-29$
True.
Hence, the solution is $(6,7)$.
