Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 30

Answer

The solution is $h=7$.

Work Step by Step

The given equation is $\Rightarrow \sqrt{8h-7}=\sqrt{6h+7}$ Square each side of the equation. $\Rightarrow (\sqrt{8h-7})^2=(\sqrt{6h+7})^2$ Simplify. $\Rightarrow 8h-7=6h+7$ Add $7-6h$ to each side. $\Rightarrow 8h-7+7-6h=6h+7+7-6h$ Simplify. $\Rightarrow 2h=14$ Divide each side by $2$. $\Rightarrow h=7$ Check $h=7$. $\Rightarrow \sqrt{8h-7}=\sqrt{6h+7}$ $\Rightarrow \sqrt{8(7)-7}=\sqrt{6(7)+7}$ $\Rightarrow \sqrt{56-7}=\sqrt{42+7}$ $\Rightarrow \sqrt{49}=\sqrt{49}$ $\Rightarrow 7=7$ True. Hence, the solution is $h=7$.
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